A translucent white waxy solid (A) reacts with excess of chlorine to give a yellowish white powder (B). (B) reacts with organic compounds containing -OH group converting them into chloro derivatives. (B) on hydrolysis gives (C) and is finally converted to phosphoric acid. (A), (B) and (C) are

Options

A. 1. `P_(4), PCl_(3), H_(3)PO_(4)`
B. 2. `P_(4), PCl_(5), H_(3)PO_(3)`
C. 3. `P_(4), PCl_(5), POCl_(3)`
D. 4. `P_(4), PCl_(3), POCl_(3)`

Explanation

To solve the question step by step, we need to identify the substances A, B, and C based on the given reactions and properties.

### Step 1: Identify Substance A
The question states that a translucent white waxy solid (A) reacts with excess chlorine to produce a yellowish white powder (B).

- The description of a "translucent white waxy solid" matches that of **white phosphorus (P4)**.

**Conclusion for Step 1:**
- A = P4 (white phosphorus)

### Step 2: Identify Substance B
Next, we need to determine what substance B is. The problem states that (B) is produced when (A) reacts with excess chlorine.

- When white phosphorus (P4) reacts with chlorine (Cl2), it forms **phosphorus pentachloride (PCl5)**, which is a yellowish white powder.

**Conclusion for Step 2:**
- B = PCl5 (phosphorus pentachloride)

### Step 3: Identify Substance C
Now we need to analyze the next part of the question, which states that (B) reacts with organic compounds containing -OH groups to convert them into chloro derivatives.

- Phosphorus pentachloride (PCl5) is known to react with alcohols (organic compounds with -OH groups) to form chloro derivatives.

Next, we look at what happens when (B) undergoes hydrolysis.

- When PCl5 is hydrolyzed, it produces **phosphoryl chloride (POCl3)** and hydrochloric acid (HCl).

**Conclusion for Step 3:**
- C = POCl3 (phosphoryl chloride)

### Step 4: Final Conversion to Phosphoric Acid
Finally, the question states that (C) on hydrolysis gives phosphoric acid.

- When phosphoryl chloride (POCl3) is hydrolyzed, it produces **phosphoric acid (H3PO4)** along with more HCl.

### Summary of Conclusions
- A = P4 (white phosphorus)
- B = PCl5 (phosphorus pentachloride)
- C = POCl3 (phosphoryl chloride)

Thus, the final answer is:
- A = P4, B = PCl5, C = POCl3