On reaction with `Cl_(2)`, phosphorus forms two types of halides 'A' and 'B'. Halide 'A' is yellowish-white powder but halide 'B' is colourless oily liquid. What would be the hydrolysis products of 'A' and 'B' respectively?

Options

A. `H_(3)PO_(4), H_(3)PO_(3)`
B. `HOPO_(3), H_(2)PO_(2)`
C. `H_(3)PO_(3), H_(3)PO_(4)`
D. `HPO_(3), H_(3)PO_(3)`

Explanation

To solve the question regarding the hydrolysis products of the two halides formed by phosphorus and chlorine, we can follow these steps:

### Step 1: Identify the Halides
The question states that phosphorus reacts with chlorine to form two types of halides, 'A' and 'B'. Based on the description:
- Halide 'A' is a yellowish-white powder, which corresponds to phosphorus pentachloride (PCl5).
- Halide 'B' is a colorless oily liquid, which corresponds to phosphorus trichloride (PCl3).

### Step 2: Write the Hydrolysis Reactions
Next, we need to determine the hydrolysis products of both halides when they react with water.

#### Hydrolysis of Halide 'A' (PCl5):
The hydrolysis reaction can be written as:
\[ \text{PCl}_5 + \text{H}_2\text{O} \rightarrow \text{H}_3\text{PO}_4 + 5 \text{HCl} \]
In this reaction, phosphorus pentachloride reacts with water to form phosphoric acid (H3PO4) and hydrochloric acid (HCl).

#### Hydrolysis of Halide 'B' (PCl3):
The hydrolysis reaction can be written as:
\[ \text{PCl}_3 + \text{H}_2\text{O} \rightarrow \text{H}_3\text{PO}_3 + 3 \text{HCl} \]
In this reaction, phosphorus trichloride reacts with water to form phosphorous acid (H3PO3) and hydrochloric acid (HCl).

### Step 3: Summarize the Hydrolysis Products
From the above reactions, we can summarize the hydrolysis products:
- Hydrolysis of Halide 'A' (PCl5) gives: **H3PO4** (phosphoric acid) and **HCl**.
- Hydrolysis of Halide 'B' (PCl3) gives: **H3PO3** (phosphorous acid) and **HCl**.

### Final Answer
The hydrolysis products of halide 'A' (PCl5) and halide 'B' (PCl3) are:
- For 'A': H3PO4
- For 'B': H3PO3