Which of the following gives correct arrangement of compounds involved based on their bond strength?

Options

A. `HF gt HCl gt HBr gt HI`
B. `HI gt HBr gt HCl gt HF`
C. `HCl gt HF gt HBr gt HI`
D. `HF gt HBr gt HCl gt HI`

Answer

To determine the correct arrangement of compounds based on their bond strength, we need to analyze the bond strength of hydrogen halides (HF, HCl, HBr, HI). The bond strength is influenced by the size of the halogen atoms and the nature of the bond formed with hydrogen.

### Step-by-Step Solution:

1. **Identify the Compounds**: The compounds we are considering are HF (hydrogen fluoride), HCl (hydrogen chloride), HBr (hydrogen bromide), and HI (hydrogen iodide).

2. **Understand Bond Strength**: Bond strength generally decreases as the size of the halogen atoms increases. This is because larger atoms lead to a longer bond length, which weakens the bond.

3. **Analyze the Halogen Size**:
- Fluorine (F) is the smallest halogen.
- Chlorine (Cl) is larger than fluorine.
- Bromine (Br) is larger than chlorine.
- Iodine (I) is the largest halogen.

4. **Determine Bond Strength Order**:
- HF has a strong bond due to the small size of fluorine.
- HCl has a weaker bond than HF due to the larger size of chlorine.
- HBr has an even weaker bond than HCl due to the larger size of bromine.
- HI has the weakest bond because iodine is the largest halogen.

5. **Establish the Correct Order**: Based on the analysis, the order of bond strength from strongest to weakest is:
- HF > HCl > HBr > HI

6. **Select the Correct Option**: From the options provided:
- Option 1: HF > HCl > HBr > HI (This is correct)
- Option 2: HI > HBr > HCl > HF (Incorrect)
- Option 3: HCl > HF > HBr > HI (Incorrect)
- Option 4: HF > HBr > HCl > HI (Incorrect)

### Conclusion:
The correct arrangement of compounds based on their bond strength is given by Option 1: HF > HCl > HBr > HI.