If chlorine is passed through a solution of hydrogen sulphide in water, the solution turns turbid due to the formation of

Options

A. free chlorine
B. free sulphur
C. nascent oxygen
D. nascent hydrogen

Explanation

To solve the question, "If chlorine is passed through a solution of hydrogen sulphide in water, the solution turns turbid due to the formation of," we will analyze the reaction step by step.

### Step-by-Step Solution

1. **Identify the Reactants**:
- The reactants in this scenario are chlorine gas (Cl2) and hydrogen sulfide (H2S) in aqueous solution.

2. **Write the Reaction**:
- When chlorine gas is bubbled through a solution of hydrogen sulfide, a chemical reaction occurs. The reaction can be represented as:
\[ Cl_2 + H_2S \rightarrow \text{Products} \]

3. **Determine the Products**:
- Chlorine (Cl2) acts as an oxidizing agent and oxidizes hydrogen sulfide (H2S). The products of this reaction are free sulfur (S) and hydrochloric acid (HCl):
\[ Cl_2 + H_2S \rightarrow S + 2HCl \]

4. **Analyze the Resulting Solution**:
- The formation of free sulfur (S) in the solution leads to the turbidity. Free sulfur is a solid that does not dissolve well in water, causing the solution to become cloudy or turbid.

5. **Conclusion**:
- Therefore, the solution turns turbid due to the formation of free sulfur. The correct answer is option 2: free sulfur.

### Final Answer
The solution turns turbid due to the formation of **free sulfur**.

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