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A black compound of manganese reacts wit...

A black compound of manganese reacts with a halogen acid to give greenish yellow gas. When excess of this gas reacts with `NH_(3) an unstable trihalide is formed. In this process the oxidation state of nitrogen changes from . . . . . . . . . .

A

`-3" to "+3 `

B

`-3" to" 0`

C

`- 3" to "+ 5`

D

`0" to "- 3`

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To solve the problem step by step, we will analyze the information provided about the black compound of manganese, its reaction with a halogen acid, and the subsequent reaction with ammonia (NH₃). ### Step 1: Identify the Black Compound of Manganese The question states that there is a black compound of manganese. The most common black compound of manganese is manganese dioxide (MnO₂). **Hint:** Look for common manganese compounds and their colors. ### Step 2: Reaction with Halogen Acid The black compound (MnO₂) reacts with a halogen acid (HX). The question specifies that the product is a greenish-yellow gas. The only halogen acid that produces a greenish-yellow gas when reacting with MnO₂ is hydrochloric acid (HCl), which produces chlorine gas (Cl₂). **Chemical Reaction:** \[ \text{MnO}_2 + 4\text{HCl} \rightarrow \text{MnCl}_2 + 2\text{Cl}_2 + 2\text{H}_2\text{O} \] **Hint:** Identify the halogen acid that produces the specified gas. ### Step 3: Excess Chlorine Gas Reaction with Ammonia The greenish-yellow gas (Cl₂) reacts with excess ammonia (NH₃) to form an unstable trihalide. The reaction can be represented as follows: **Chemical Reaction:** \[ 3\text{NH}_3 + 3\text{Cl}_2 \rightarrow 3\text{NCl}_3 + 3\text{HCl} \] **Hint:** Recognize that chlorine reacts with ammonia to form nitrogen trichloride (NCl₃). ### Step 4: Determine the Oxidation States of Nitrogen Now, we need to determine the change in the oxidation state of nitrogen during this reaction. 1. **In Ammonia (NH₃):** - Let the oxidation state of nitrogen be \( x \). - The oxidation state of hydrogen is +1. - The overall charge of NH₃ is 0: \[ x + 3(+1) = 0 \implies x + 3 = 0 \implies x = -3 \] 2. **In Nitrogen Trichloride (NCl₃):** - Let the oxidation state of nitrogen be \( y \). - The oxidation state of chlorine is -1. - The overall charge of NCl₃ is 0: \[ y + 3(-1) = 0 \implies y - 3 = 0 \implies y = +3 \] ### Step 5: Calculate the Change in Oxidation State The oxidation state of nitrogen changes from -3 (in NH₃) to +3 (in NCl₃). **Final Answer:** The oxidation state of nitrogen changes from -3 to +3. ### Summary of Steps: 1. Identify the black compound of manganese as MnO₂. 2. Recognize that MnO₂ reacts with HCl to produce Cl₂ gas. 3. Understand that Cl₂ reacts with NH₃ to form NCl₃. 4. Calculate the oxidation states of nitrogen in NH₃ and NCl₃. 5. Conclude that the oxidation state of nitrogen changes from -3 to +3.

To solve the problem step by step, we will analyze the information provided about the black compound of manganese, its reaction with a halogen acid, and the subsequent reaction with ammonia (NH₃). ### Step 1: Identify the Black Compound of Manganese The question states that there is a black compound of manganese. The most common black compound of manganese is manganese dioxide (MnO₂). **Hint:** Look for common manganese compounds and their colors. ### Step 2: Reaction with Halogen Acid ...
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