Dinucleotide is obtained by joining two nucleotides together by phosphodiester linkage. Between which carbon atoms of pentose sugars of nucleotides are these linkages present ?

Options

A. 5' and 3'
B. 1' and 5'
C. 5' and 5'
D. 3' and 3'

Explanation

To answer the question regarding the formation of dinucleotides through phosphodiester linkages, we will break down the process step by step.

### Step-by-Step Solution:

1. **Understanding Nucleotides**:
- A nucleotide is composed of three components: a phosphate group, a pentose sugar (either ribose or deoxyribose), and a nitrogenous base.

2. **Structure of Pentose Sugar**:
- The pentose sugar in nucleotides has five carbon atoms, numbered from 1' to 5'. The 1' carbon is attached to the nitrogenous base, the 5' carbon is attached to the phosphate group, and the 3' carbon has a hydroxyl (-OH) group.

3. **Phosphodiester Linkage**:
- A dinucleotide is formed when two nucleotides are joined together. This joining occurs through a specific type of bond known as a phosphodiester bond.

4. **Formation of the Bond**:
- The phosphodiester bond is formed between the 5' carbon of one nucleotide and the 3' carbon of the adjacent nucleotide.
- Specifically, the phosphate group attached to the 5' carbon of the first nucleotide forms a bond with the hydroxyl group on the 3' carbon of the second nucleotide.

5. **Conclusion**:
- Therefore, the phosphodiester linkage in a dinucleotide is present between the 5' carbon of one nucleotide and the 3' carbon of another nucleotide.

### Final Answer:
The phosphodiester linkage in a dinucleotide is present between the 5' carbon of one nucleotide and the 3' carbon of the adjacent nucleotide.

---