Hydrolysis of `SiCl_(4)` gives

Options

A. `Si(OH)_(4)`
B. `SiOCI_(2)`
C. `SiO_(2)`
D. `H_(2)SiO_(4)`

Explanation

To solve the question regarding the hydrolysis of SiCl₄, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Hydrolysis**: Hydrolysis is a chemical reaction where water (H₂O) is added to a substance, leading to the breakdown of that substance.

2. **Identify the Reactants**: In this case, the reactant is silicon tetrachloride (SiCl₄).

3. **Write the Reaction**: When SiCl₄ undergoes hydrolysis, it reacts with water. The reaction can be written as:
\[ \text{SiCl}_4 + \text{4 H}_2\text{O} \rightarrow \text{Si(OH)}_4 + \text{4 HCl} \]

4. **Identify the Products**: The products of this reaction are:
- Silicic acid (Si(OH)₄)
- Hydrochloric acid (HCl)

5. **Balance the Reaction**: Ensure that the number of atoms of each element is the same on both sides of the equation. In this case, the reaction is already balanced:
- 1 Si atom on both sides
- 4 Cl atoms on both sides
- 8 H atoms (from 4 H₂O and 4 HCl) on both sides
- 4 O atoms on both sides

6. **Conclusion**: The hydrolysis of SiCl₄ produces silicic acid (Si(OH)₄) and hydrochloric acid (HCl).

### Final Answer:
The hydrolysis of SiCl₄ gives silicic acid (Si(OH)₄) and hydrochloric acid (HCl).

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