Peroxodisulphate, on hydrolysis yields

Options

A. water
B. dihydrogen
C. hydrogen peroxide
D. deuterium.

Explanation

To solve the question regarding the hydrolysis of peroxodisulfate, we will follow these steps:

### Step 1: Identify the structure of peroxodisulfate
Peroxodisulfate is represented as \( \text{S}_2\text{O}_8^{2-} \). It contains two sulfate groups (\( \text{SO}_4^{2-} \)) linked by a peroxide bond (O-O).

### Step 2: Write the hydrolysis reaction
When peroxodisulfate undergoes hydrolysis, it reacts with water. The reaction can be represented as follows:
\[ \text{S}_2\text{O}_8^{2-} + 2 \text{H}_2\text{O} \rightarrow 2 \text{HSO}_4^{-} + 2 \text{H}^{+} + \text{H}_2\text{O}_2 \]

### Step 3: Identify the products
From the hydrolysis reaction, we can see that the products formed are:
- Two hydrogen sulfate ions (\( \text{HSO}_4^{-} \))
- Two hydrogen ions (\( \text{H}^{+} \))
- One molecule of hydrogen peroxide (\( \text{H}_2\text{O}_2 \))

### Conclusion
Thus, the hydrolysis of peroxodisulfate yields:
\[ 2 \text{HSO}_4^{-} + 2 \text{H}^{+} + \text{H}_2\text{O}_2 \]

### Final Answer
The answer to the question is that peroxodisulfate on hydrolysis yields \( 2 \text{HSO}_4^{-} + 2 \text{H}^{+} + \text{H}_2\text{O}_2 \).

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