Home
Class 11
CHEMISTRY
Strength of 10 volume hydrogen peroxide ...

Strength of 10 volume hydrogen peroxide solution means

A

`30.36 gL^(-1)`

B

`17 gL^(-1)`

C

`34 gL^(-1)`

D

`68 gL^(-1)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the strength of a 10 volume hydrogen peroxide (H2O2) solution, we can follow these steps: ### Step 1: Understand the Concept of Volume Strength The term "10 volume" means that 1 liter of the hydrogen peroxide solution can produce 10 liters of oxygen gas (O2) at normal temperature and pressure (NTP). ### Step 2: Write the Reaction Equation The decomposition of hydrogen peroxide can be represented by the following balanced chemical equation: \[ 2 \, \text{H}_2\text{O}_2 \rightarrow 2 \, \text{H}_2\text{O} + \text{O}_2 \] ### Step 3: Determine Moles of H2O2 Required From the balanced equation, we see that 2 moles of H2O2 produce 1 mole of O2. Therefore, to produce 10 liters of O2, we need to calculate how many moles of H2O2 are required. ### Step 4: Calculate Moles of O2 At NTP, 1 mole of gas occupies 22.4 liters. Therefore, the number of moles of O2 produced from 10 liters is: \[ \text{Moles of O2} = \frac{10 \, \text{liters}}{22.4 \, \text{liters/mole}} \approx 0.4464 \, \text{moles} \] ### Step 5: Calculate Moles of H2O2 Required Since 2 moles of H2O2 produce 1 mole of O2, the moles of H2O2 required to produce 0.4464 moles of O2 is: \[ \text{Moles of H2O2} = 2 \times 0.4464 \approx 0.8928 \, \text{moles} \] ### Step 6: Calculate Mass of H2O2 The molar mass of H2O2 is calculated as follows: - Hydrogen (H) = 1 g/mol, so for 2 H: \(2 \times 1 = 2 \, \text{g/mol}\) - Oxygen (O) = 16 g/mol, so for 2 O: \(2 \times 16 = 32 \, \text{g/mol}\) - Total molar mass of H2O2 = \(2 + 32 = 34 \, \text{g/mol}\) Now, we can calculate the mass of H2O2 required: \[ \text{Mass of H2O2} = \text{Moles} \times \text{Molar Mass} = 0.8928 \, \text{moles} \times 34 \, \text{g/mol} \approx 30.36 \, \text{grams} \] ### Step 7: Determine Strength of the Solution Since the strength of the solution is expressed in grams per liter, we conclude that the strength of a 10 volume hydrogen peroxide solution is: \[ \text{Strength} = 30.36 \, \text{grams per liter} \] ### Final Answer The strength of a 10 volume hydrogen peroxide solution is **30.36 grams per liter**. ---

To determine the strength of a 10 volume hydrogen peroxide (H2O2) solution, we can follow these steps: ### Step 1: Understand the Concept of Volume Strength The term "10 volume" means that 1 liter of the hydrogen peroxide solution can produce 10 liters of oxygen gas (O2) at normal temperature and pressure (NTP). ### Step 2: Write the Reaction Equation The decomposition of hydrogen peroxide can be represented by the following balanced chemical equation: \[ ...
Promotional Banner

Topper's Solved these Questions

  • HYDROGEN

    NCERT FINGERTIPS ENGLISH|Exercise HOTS (HIGHER ORDER THINKING SKILLS)|9 Videos
  • HYDROGEN

    NCERT FINGERTIPS ENGLISH|Exercise NCERT (EXEMPLAR PROBLEMS)|18 Videos
  • HYDROCARBONS

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|15 Videos
  • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

    NCERT FINGERTIPS ENGLISH|Exercise Assertion And Reason|12 Videos

Similar Questions

Explore conceptually related problems

Hydrogen peroxide is

Calculate the strength of a 40 volume hydrogen peroxide solution in gL^(-1)

20 volume hydrogen peroxide means

30- volume hydrogen peroxide means

Calculate the normality of 18 volume hydrogen peroxide solution .

There is a smaple of 10 volume of hydrogen peroxide solution . Calculate its strength.

There is a smaple of 10 volume of hydrogen peroxide solution . Calculate its strength.

Calculate the strength in g L^(- 1) and normality of '30 volume' hydrogen peroxide solution.

The strengths of 5.6 volume hydrogen peroxide (of density 1g/ mL) in terms of mass percentage and molarity (M) , respectively are : (Take molar mass of hydrogen peroxide as 34g / mol )

Calculate the volume strength of a hydrogen peroxide solution containing 60.7 g L^(-1) of H_(2)O_(2) .