Which compound is formed when calcium carbide reacts with heavy water?

Options

A. `C_(2)D_(2)`
B. `CaD_(2)`
C. `CD_(2)`
D. `Ca_(2)D_(2)`

Explanation

To determine the compound formed when calcium carbide reacts with heavy water, we can follow these steps:

### Step 1: Identify the Reactants
- Calcium carbide has the chemical formula \( \text{CaC}_2 \).
- Heavy water is represented as \( \text{D}_2\text{O} \), where \( \text{D} \) stands for deuterium, an isotope of hydrogen.

### Step 2: Write the Reaction
When calcium carbide reacts with heavy water, the reaction can be represented as:
\[ \text{CaC}_2 + \text{D}_2\text{O} \rightarrow \text{Ca(OD)}_2 + \text{C}_2\text{D}_2 \]
In this reaction:
- \( \text{Ca(OD)}_2 \) is calcium hydroxide where the hydrogen atoms are replaced by deuterium.
- \( \text{C}_2\text{D}_2 \) is the product formed from the carbide.

### Step 3: Identify the Products
From the reaction, the products are:
1. Calcium deuteroxide \( \text{Ca(OD)}_2 \)
2. Deuterated acetylene \( \text{C}_2\text{D}_2 \)

### Step 4: Conclusion
The main compound formed when calcium carbide reacts with heavy water is deuterated acetylene \( \text{C}_2\text{D}_2 \).

### Final Answer
The compound formed when calcium carbide reacts with heavy water is \( \text{C}_2\text{D}_2 \).

---