Which of the following equations depict the oxidising nature of `H_(2)O_(2)` ?

Options

A. `2MnO_(4)^(-)+6H^(+)+5H_(2)O_(2)rarr 2Mn^(2+)+8H_(2)O+5O_(2)`
B. `2Fe^(3+)+2H^(+)+H_(2)O_(2)rarr 2Fe^(2+)+2H_(2)O+O_(2)`
C. `2I^(-)+2H^(+)+H_(2)O_(2)rarr I_(2)+2H_(2)O`
D. `KIO_(4)+H_(2)O_(2)rarr KIO_(3)+H_(2)O+O_(2)`

Explanation

To determine which of the given equations depict the oxidizing nature of hydrogen peroxide (H₂O₂), we need to identify reactions where H₂O₂ acts as an oxidizing agent. An oxidizing agent is a substance that oxidizes other species by accepting electrons and, in the process, gets reduced itself.

### Step-by-step Solution:

1. **Understand Oxidation and Reduction**:
- Oxidation is the process of losing electrons.
- Reduction is the process of gaining electrons.
- An oxidizing agent causes oxidation in another substance while being reduced itself.

2. **Identify the Reactions**:
- We need to analyze the given reactions to see which one shows a species being oxidized (losing electrons) while H₂O₂ acts as the oxidizing agent.

3. **Examine Each Reaction**:
- **Reaction 1**: MnO₄⁻ → Mn²⁺
- Here, Mn changes from +7 to +2, which means it is gaining electrons (reduction). Thus, this reaction does not depict the oxidizing nature of H₂O₂.

- **Reaction 2**: Fe³⁺ → Fe²⁺
- In this case, Fe is also gaining electrons (reduction), moving from +3 to +2. This reaction does not show the oxidizing nature of H₂O₂ either.

- **Reaction 3**: I⁻ → I₂
- Here, Iodide (I⁻) is being converted to I₂. The oxidation state changes from -1 to 0, indicating that I⁻ is losing electrons (oxidation). Thus, H₂O₂ is acting as the oxidizing agent in this reaction.

- **Reaction 4**: KI₄ → KI₃
- In this reaction, the oxidation state of Iodine changes from +7 to +5, indicating that it is gaining electrons (reduction). Therefore, this reaction does not depict the oxidizing nature of H₂O₂.

4. **Conclusion**:
- The only reaction where H₂O₂ acts as an oxidizing agent is the third one (I⁻ → I₂). Therefore, the correct answer is option C.

### Final Answer:
**Option C** depicts the oxidizing nature of H₂O₂.