When sodium peroxide is trated with the dilute sulphuric acid, we get.

Options

A. sodium sulphate and water
B. sodium sulphate and oxygen
C. sodium sulphate, hydrogen and oxygen
D. sodium sulphate and hydrogen peroxide

Explanation

To solve the problem of what products are formed when sodium peroxide (Na2O2) is treated with dilute sulfuric acid (H2SO4), we can follow these steps:

### Step 1: Write the Reactants
Identify the reactants in the reaction:
- Sodium peroxide (Na2O2)
- Dilute sulfuric acid (H2SO4)

### Step 2: Write the Chemical Reaction
The chemical reaction can be represented as:
\[ \text{Na}_2\text{O}_2 + \text{H}_2\text{SO}_4 \rightarrow ? \]

### Step 3: Identify the Products
When sodium peroxide reacts with dilute sulfuric acid, it typically produces sodium sulfate (Na2SO4) and hydrogen peroxide (H2O2). Therefore, we can write the balanced equation as:
\[ \text{Na}_2\text{O}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + \text{H}_2\text{O}_2 \]

### Step 4: Conclusion
From the balanced equation, we can conclude that the products of the reaction are:
- Sodium sulfate (Na2SO4)
- Hydrogen peroxide (H2O2)

Thus, the correct answer to the question is:
**D: Sodium sulfate and hydrogen peroxide.**

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