Which type of hybridisation of each carbon is there in the compound?
`CH_(3)-CH=CH-CN`

Options

A. `sp^(3),sp^(2),sp^(2),sp`
B. `sp^(3),sp^(2),sp^(2),sp^(3)`
C. `sp^(3),sp^(2),sp^(3),sp^(3)`
D. `sp^(3),sp^(2),sp,sp^(3)`

Answer

To determine the hybridization of each carbon in the compound \( CH_3-CH=CH-CN \), we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure**:
The compound can be represented as follows:
- Carbon 1 (C1) is part of the \( CH_3 \) group.
- Carbon 2 (C2) is the carbon that is double-bonded to C3.
- Carbon 3 (C3) is the carbon that is double-bonded to C2 and single-bonded to C4.
- Carbon 4 (C4) is bonded to the nitrogen (CN).

2. **Number the Carbons**:
- C1: \( CH_3 \)
- C2: \( CH \) (double bond with C3)
- C3: \( CH \) (double bond with C2 and single bond with C4)
- C4: \( CN \)

3. **Count the Attached Atoms**:
- For C1: It has 3 hydrogen atoms and is connected to C2 (total 4 atoms).
- For C2: It has 1 hydrogen atom, 1 double bond with C3, and is connected to C1 (total 3 atoms).
- For C3: It has 1 hydrogen atom, 1 double bond with C2, and is connected to C4 (total 3 atoms).
- For C4: It has 1 carbon atom (C3) and 1 nitrogen atom (total 2 atoms).

4. **Determine Hybridization**:
- **C1**: 4 atoms attached → Hybridization is \( sp^3 \).
- **C2**: 3 atoms attached → Hybridization is \( sp^2 \).
- **C3**: 3 atoms attached → Hybridization is \( sp^2 \).
- **C4**: 2 atoms attached → Hybridization is \( sp \).

5. **Summarize the Hybridization**:
- C1: \( sp^3 \)
- C2: \( sp^2 \)
- C3: \( sp^2 \)
- C4: \( sp \)

### Final Answer:
The hybridization of each carbon in the compound \( CH_3-CH=CH-CN \) is:
- C1: \( sp^3 \)
- C2: \( sp^2 \)
- C3: \( sp^2 \)
- C4: \( sp \)