Which of the following represents the given sequence of hybridisation of carbon atoms from left to right `sp^(2),sp^(2),sp,sp`?

Options

A. `H_(2)C=CH-C-=CH`
B. `HC-=C-CH=CH_(2)`
C. `H_(3)C-CH=CH-CH_(3)`
D. `H_(2)C=CH-CH=CH_(2)`

Answer

To determine the structure that corresponds to the given sequence of hybridization of carbon atoms from left to right as `sp²`, `sp²`, `sp`, and `sp`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Hybridization Types**:
- The first two carbon atoms are `sp²` hybridized.
- The third carbon atom is `sp` hybridized.
- The fourth carbon atom is also `sp` hybridized.

2. **Understand the Hybridization**:
- `sp²` hybridization indicates that each of these carbon atoms is bonded to three other atoms (one double bond or two single bonds).
- `sp` hybridization indicates that each of these carbon atoms is bonded to two other atoms (one triple bond or two single bonds).

3. **Construct the Structure**:
- Start with the first carbon (C1) which is `sp²`. It can form one double bond and two single bonds. We can represent it as `C1 = CH₂` (two hydrogens).
- The second carbon (C2) is also `sp²`. It can form a double bond with C1 and single bond with another carbon (C3). Thus, we can represent it as `C2 = CH`.
- The third carbon (C3) is `sp`. It can form a triple bond with the fourth carbon (C4) and a single bond with C2. Thus, we can represent it as `C3 = C`.
- The fourth carbon (C4) is also `sp`. It can form a triple bond with C3 and a single bond with hydrogen. Thus, we can represent it as `C4 = CH`.

4. **Combine the Atoms**:
- Now we can combine these representations:
- C1 (CH₂) double bonds with C2 (CH), which in turn single bonds with C3 (C), which triple bonds with C4 (CH).
- The overall structure can be represented as:
- `CH₂ = CH - C ≡ CH`.

5. **Final Structure**:
- The final structure is `CH₂=CH-C≡CH`, which corresponds to the given sequence of hybridization.

### Conclusion:
The structure that represents the given sequence of hybridization of carbon atoms from left to right `sp²`, `sp²`, `sp`, `sp` is `CH₂=CH-C≡CH`.