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How many primary, secondary, tertiary an...

How many primary, secondary, tertiary and quaternary carbon atoms are present in the following compound?
`CH_(3)-underset(CH_(3))underset(|)(C)H-CH_(2)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)`

A

One primary, two secondary and one tertiary

B

Five primary, three secondary

C

Five primary, one secondary, one tertiary and one quaternary

D

four primary, two secondary and two quaternary

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of primary, secondary, tertiary, and quaternary carbon atoms in the given compound, we will follow these steps: ### Step 1: Understand the Definitions - **Primary Carbon (1°)**: A carbon atom bonded to three hydrogen atoms (–CH₃). - **Secondary Carbon (2°)**: A carbon atom bonded to two hydrogen atoms and one carbon atom (–CH₂–). - **Tertiary Carbon (3°)**: A carbon atom bonded to one hydrogen atom and two carbon atoms (–CH–). - **Quaternary Carbon (4°)**: A carbon atom bonded to no hydrogen atoms and four carbon atoms (–C–). ### Step 2: Draw the Structure The compound can be represented as follows: ``` CH₃ | CH₃ - C - CH₂ - C - CH₃ | CH₃ ``` Number the carbon atoms from left to right: 1. C1 2. C2 3. C3 4. C4 5. C5 6. C6 7. C7 8. C8 ### Step 3: Analyze Each Carbon Atom - **C1**: Bonded to 3 H atoms → Primary (1°) - **C2**: Bonded to 1 H atom and 2 C atoms → Tertiary (3°) - **C3**: Bonded to 3 H atoms → Primary (1°) - **C4**: Bonded to 2 H atoms and 1 C atom → Secondary (2°) - **C5**: Bonded to 3 H atoms → Primary (1°) - **C6**: Bonded to 0 H atoms and 4 C atoms → Quaternary (4°) - **C7**: Bonded to 3 H atoms → Primary (1°) - **C8**: Bonded to 3 H atoms → Primary (1°) ### Step 4: Count Each Type of Carbon - **Primary Carbons (1°)**: C1, C3, C5, C7, C8 → Total = 5 - **Secondary Carbons (2°)**: C4 → Total = 1 - **Tertiary Carbons (3°)**: C2 → Total = 1 - **Quaternary Carbons (4°)**: C6 → Total = 1 ### Final Count - **Primary Carbons**: 5 - **Secondary Carbons**: 1 - **Tertiary Carbons**: 1 - **Quaternary Carbons**: 1 ### Conclusion The compound contains: - 5 primary carbon atoms - 1 secondary carbon atom - 1 tertiary carbon atom - 1 quaternary carbon atom
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