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The type of isomerism shown by the follo...

The type of isomerism shown by the following compounds is
`CH_(3)CH_(2)CH_(2)CH_(2)CH_(3),CH_(3)-overset(CH_(3))overset(|)(C)H-CH_(2)CH_(3),CH_(3)-underset(CH_(3))underset(|)overset(CH_(3))overset(|)(C)-CH_(3)`

A

position isomerism

B

metamerism

C

ring-chain isomerism

D

chain isomerism

Text Solution

AI Generated Solution

The correct Answer is:
To determine the type of isomerism shown by the given compounds, we will analyze the structures of each compound and identify their characteristics. ### Step-by-Step Solution: 1. **Identify the Compounds**: - The first compound is `CH3CH2CH2CH2CH3`, which is n-pentane (a straight-chain alkane with five carbon atoms). - The second compound is `CH3-CH(CH3)-CH2CH3`, which is 2-methylbutane (a branched-chain alkane). - The third compound is `CH3-CH(CH3)-C(CH3)H-CH3`, which is 2,2-dimethylbutane (another branched-chain alkane). 2. **Determine the Molecular Formula**: - All three compounds have the same molecular formula, C5H12, indicating they are isomers of each other. 3. **Classify the Isomerism**: - **Chain Isomerism**: This occurs when the compounds have the same molecular formula but differ in the arrangement of the carbon skeleton. - In this case: - n-pentane has a straight chain. - 2-methylbutane has a branched chain with a methyl group on the second carbon. - 2,2-dimethylbutane has a more branched structure with two methyl groups on the second carbon. 4. **Conclusion**: - Since all three compounds have the same molecular formula (C5H12) but differ in the structure of the carbon chain, they exhibit **chain isomerism**. ### Final Answer: The type of isomerism shown by the compounds `CH3CH2CH2CH2CH3`, `CH3-CH(CH3)-CH2CH3`, and `CH3-CH(CH3)-C(CH3)H-CH3` is **chain isomerism**.
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