In Carium method of estimation of halgoen, 0.15 g of an organic compound gave 0.12 g of AgBr. What is the percentage of bromine in the compound?

Options

A. 0.6808
B. 0.3504
C. `42.1%`
D. 0.5

Explanation

To find the percentage of bromine in the organic compound using the Carium method of estimation of halogens, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given data:**
- Mass of the organic compound = 0.15 g
- Mass of AgBr produced = 0.12 g
- Molar mass of bromine (Br) = 80 g/mol
- Molar mass of AgBr = 188 g/mol

2. **Calculate the mass of bromine in AgBr:**
- The mass of bromine in AgBr can be calculated using the ratio of the molar masses:
\[ \text{Mass of Br} = \left( \frac{\text{Molar mass of Br}}{\text{Molar mass of AgBr}} \right) \times \text{Mass of AgBr} \]
- Substituting the values:
\[ \text{Mass of Br} = \left( \frac{80}{188} \right) \times 0.12 \]

3. **Calculate the mass of bromine:**
- Performing the calculation:
\[ \text{Mass of Br} = \left( 0.4255 \right) \times 0.12 = 0.05106 \text{ g} \]

4. **Calculate the percentage of bromine in the organic compound:**
- The percentage of bromine is calculated using the formula:
\[ \text{Percentage of Br} = \left( \frac{\text{Mass of Br}}{\text{Mass of organic compound}} \right) \times 100 \]
- Substituting the values:
\[ \text{Percentage of Br} = \left( \frac{0.05106}{0.15} \right) \times 100 \]

5. **Perform the final calculation:**
- Calculating the percentage:
\[ \text{Percentage of Br} = 0.3404 \times 100 = 34.04\% \]

### Final Answer:
The percentage of bromine in the organic compound is **34.04%**.