2.18g of an organic compound containing sulphur produces 1.02 g of `BaSO_(4)`. The percentage of sulphur in the compound is

Options

A. 0.0726
B. 0.0898
C. 0.1
D. 0.0642

Explanation

To find the percentage of sulfur in the organic compound, we can follow these steps:

### Step 1: Determine the mass of sulfur in BaSO₄
We know that 1.02 g of BaSO₄ is produced. To find the mass of sulfur in BaSO₄, we first need to calculate the molar mass of BaSO₄.

**Molar mass of BaSO₄:**
- Barium (Ba) = 137 g/mol
- Sulfur (S) = 32 g/mol
- Oxygen (O) = 16 g/mol × 4 = 64 g/mol

Total molar mass of BaSO₄ = 137 + 32 + 64 = 233 g/mol

### Step 2: Calculate the mass of sulfur in BaSO₄
Using the mass of BaSO₄ produced, we can find the mass of sulfur:

\[ \text{Mass of sulfur} = \left( \frac{\text{mass of S in BaSO₄}}{\text{molar mass of BaSO₄}} \right) \times \text{mass of BaSO₄} \]

The mass of sulfur in BaSO₄ is 32 g (from the molar mass calculation).

\[ \text{Mass of sulfur} = \left( \frac{32}{233} \right) \times 1.02 \text{ g} \]

### Step 3: Calculate the mass of sulfur
Now, we can calculate the mass of sulfur:

\[ \text{Mass of sulfur} = \left( \frac{32}{233} \right) \times 1.02 \approx 0.139 \text{ g} \]

### Step 4: Calculate the percentage of sulfur in the organic compound
Now that we have the mass of sulfur, we can calculate the percentage of sulfur in the original organic compound:

\[ \text{Percentage of sulfur} = \left( \frac{\text{mass of sulfur}}{\text{mass of organic compound}} \right) \times 100 \]

Substituting the values:

\[ \text{Percentage of sulfur} = \left( \frac{0.139}{2.18} \right) \times 100 \]

### Step 5: Calculate the final percentage
Now, we can calculate the percentage:

\[ \text{Percentage of sulfur} \approx 6.38\% \]

### Final Answer
The percentage of sulfur in the organic compound is approximately **6.38%**.

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