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Which of the following orders correctly ...

Which of the following orders correctly depicts the decreasing order of stability of carbanion?

A

B

`OHC-underset(CHO)underset(|)overline(C)-CHO gt OHC- overline(C)H-CHO gt H_(3)C- underset(O)underset(||)(C)-overline(C)H-underset(O)underset(||)(C)-CH_(3) gt overline(C)H_(3)-CHO`

C

`overline(C)H_(2)NO_(2) lt overline(C)H_(2)CN lt overline(C)H_(2)Cl lt overline(C)H_(2)CH_(3)`

D

Text Solution

AI Generated Solution

The correct Answer is:
To determine the decreasing order of stability of carbanions, we need to consider the effect of substituents on the carbanion. The stability of carbanions is influenced by the presence of electron-withdrawing groups (EWGs) and electron-donating groups (EDGs). ### Step-by-Step Solution: 1. **Understanding Carbanion Stability**: - Carbanions are negatively charged carbon species. Their stability is primarily influenced by the nature of substituents attached to the carbon atom bearing the negative charge. - Electron-withdrawing groups stabilize carbanions by delocalizing the negative charge, while electron-donating groups destabilize them by increasing electron density. 2. **Identifying Electron-Withdrawing and Electron-Donating Groups**: - Common electron-withdrawing groups include: -NO2 (nitro), -CN (cyano), -CHO (aldehyde), and -CO (ketone). - Common electron-donating groups include: -CH3 (methyl), -OCH3 (methoxy), and other alkyl groups. 3. **Analyzing the Given Options**: - **Option 1**: Contains electron-donating groups, which would destabilize the carbanion. - **Option 2**: Contains multiple -CHO groups, which are strong electron-withdrawing groups. This option is likely to be the most stable. - **Option 3**: Contains a mix of electron-donating (CH3) and electron-withdrawing groups (Cl, CN, NO2), but the presence of CH3 destabilizes it. - **Option 4**: Contains an electron-donating group (OCH3) which destabilizes the carbanion, making it incorrect. 4. **Conclusion**: - After analyzing the effects of the substituents in each option, **Option 2** is the correct answer as it has the highest number of electron-withdrawing groups, thus stabilizing the carbanion the most. ### Final Answer: The correct order depicting the decreasing order of stability of carbanions is given by **Option 2**.
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