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Electronegativity of carbon atoms depend...

Electronegativity of carbon atoms depends upon their state of hybridisation. In which of the following compounds, the carbon marked with asterisk is most electronegative?

A

`CH_(3)-CH_(2)-CH_(2)-CH_(3)`

B

`CH_(3)-overset(***)(C)H=CH-CH_(3)`

C

`CH_(3)-CH_(2)-C-=overset(***)(C)H`

D

`CH_(3)-CH_(2)-CH=overset(***)(C)H_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which carbon atom marked with an asterisk is the most electronegative based on its hybridization state, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Electronegativity and Hybridization**: Electronegativity of carbon is influenced by its hybridization state. The more s-character in the hybridization, the more electronegative the carbon atom. The hybridization states and their corresponding s-character are: - sp hybridization: 50% s-character - sp² hybridization: 33.33% s-character - sp³ hybridization: 25% s-character 2. **Analyze Each Compound**: We need to look at the compounds given in the options and identify the hybridization of the carbon atom marked with an asterisk in each case. 3. **Determine Hybridization for Each Option**: - **Option A**: The carbon marked with an asterisk forms 4 sigma bonds (no lone pairs), indicating sp³ hybridization. - **Option B**: The carbon marked with an asterisk forms 3 sigma bonds and 1 pi bond (the pi bond does not count towards hybridization), indicating sp² hybridization. - **Option C**: The carbon marked with an asterisk forms 2 sigma bonds and 2 pi bonds (only sigma bonds count), indicating sp hybridization. - **Option D**: The carbon marked with an asterisk forms 3 sigma bonds and 1 pi bond, indicating sp² hybridization. 4. **Compare Electronegativity Based on Hybridization**: - From the analysis: - Option A (sp³) has the least electronegativity. - Option B (sp²) has intermediate electronegativity. - Option C (sp) has the highest electronegativity. - Option D (sp²) also has intermediate electronegativity. 5. **Conclusion**: The carbon marked with an asterisk in **Option C** is the most electronegative because it is sp hybridized, which has the highest s-character (50%). ### Final Answer: The carbon marked with an asterisk is most electronegative in **Option C**. ---

To determine which carbon atom marked with an asterisk is the most electronegative based on its hybridization state, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Electronegativity and Hybridization**: Electronegativity of carbon is influenced by its hybridization state. The more s-character in the hybridization, the more electronegative the carbon atom. The hybridization states and their corresponding s-character are: - sp hybridization: 50% s-character - sp² hybridization: 33.33% s-character ...
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