The strongest bond is present in

Options

A. `Br_(2)`
B. `I_(2)`
C. `Cl_(2)`
D. `F_(2)`

Answer

To determine which bond is the strongest among the halogens (F2, Cl2, Br2, and I2), we will analyze the bond lengths and bond strengths of these diatomic molecules.

### Step-by-Step Solution

1. **Understanding Bond Strength and Bond Length**:
- Bond strength is inversely proportional to bond length. This means that as bond length increases, bond strength decreases.

2. **Order of Bond Length**:
- The bond lengths of the halogen diatomic molecules can be arranged from shortest to longest:
- F2 (Fluorine) < Cl2 (Chlorine) < Br2 (Bromine) < I2 (Iodine)
- This indicates that F2 has the shortest bond length, while I2 has the longest bond length.

3. **Analyzing Bond Strength**:
- Since bond strength is inversely related to bond length, we can infer the following order of bond strength:
- I2 (weakest) < Br2 < Cl2 < F2 (strongest)
- However, we need to consider the electron density and lone pair repulsion in these bonds.

4. **Lone Pair Repulsion**:
- Fluorine has three lone pairs on each atom, which leads to significant repulsion between them. This high repulsion weakens the F-F bond despite its short length.
- Chlorine also has lone pairs, but the repulsion is less intense than that in fluorine due to the larger size of chlorine atoms.

5. **Final Comparison**:
- Although F2 has a short bond length, the high repulsion makes it a weak bond.
- Cl2 has a longer bond length than F2 but is stronger due to lower lone pair repulsion.
- Therefore, the bond strength order is:
- Cl2 > F2 > Br2 > I2

6. **Conclusion**:
- The strongest bond among the given options is in Cl2 (Chlorine).