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The ratio of specific charge of a proton...

The ratio of specific charge of a proton and an `alpha`-particle is

A

`2:1`

B

`1:2`

C

`1:4`

D

`1:1`

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The correct Answer is:
To find the ratio of the specific charge of a proton to that of an alpha particle, we will follow these steps: ### Step 1: Understand Specific Charge The specific charge of a particle is defined as the ratio of its charge (Q) to its mass (m): \[ \text{Specific Charge} = \frac{Q}{m} \] ### Step 2: Calculate the Specific Charge of a Proton The charge of a proton (Q_p) is: \[ Q_p = +1.6 \times 10^{-19} \text{ C} \] The mass of a proton (m_p) is: \[ m_p = 1.66 \times 10^{-27} \text{ kg} \] Now, we can calculate the specific charge of the proton: \[ \text{Specific Charge of Proton} = \frac{Q_p}{m_p} = \frac{1.6 \times 10^{-19}}{1.66 \times 10^{-27}} \] ### Step 3: Calculate the Specific Charge of an Alpha Particle An alpha particle consists of 2 protons and 2 neutrons, and it has a charge of: \[ Q_{\alpha} = +2 \times 1.6 \times 10^{-19} \text{ C} = 3.2 \times 10^{-19} \text{ C} \] The mass of an alpha particle (m_α) is approximately: \[ m_{\alpha} = 4 \text{ AMU} = 4 \times 1.66 \times 10^{-27} \text{ kg} = 6.64 \times 10^{-27} \text{ kg} \] Now, we can calculate the specific charge of the alpha particle: \[ \text{Specific Charge of Alpha Particle} = \frac{Q_{\alpha}}{m_{\alpha}} = \frac{3.2 \times 10^{-19}}{6.64 \times 10^{-27}} \] ### Step 4: Calculate the Ratio of Specific Charges Now, we need to find the ratio of the specific charge of a proton to that of an alpha particle: \[ \text{Ratio} = \frac{\text{Specific Charge of Proton}}{\text{Specific Charge of Alpha Particle}} = \frac{\frac{1.6 \times 10^{-19}}{1.66 \times 10^{-27}}}{\frac{3.2 \times 10^{-19}}{6.64 \times 10^{-27}}} \] ### Step 5: Simplify the Ratio This can be simplified as follows: \[ \text{Ratio} = \frac{1.6 \times 10^{-19} \times 6.64 \times 10^{-27}}{3.2 \times 10^{-19} \times 1.66 \times 10^{-27}} \] Notice that \(1.6 \times 10^{-19}\) cancels with \(3.2 \times 10^{-19}\) and \(1.66 \times 10^{-27}\) cancels with \(6.64 \times 10^{-27}\): \[ \text{Ratio} = \frac{1}{2} \] ### Final Result Thus, the ratio of the specific charge of a proton to that of an alpha particle is: \[ \text{Ratio} = 2:1 \]
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