According to Bohr's theory, the angular momentum for an electron of `5^(th)` orbit is

Options

A. `2.5h//pi`
B. `5h//pi`
C. `25h//pi`
D. `6h//2pi`

Answer

To find the angular momentum of an electron in the 5th orbit according to Bohr's theory, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Formula**: According to Bohr's theory, the angular momentum (L) of an electron in the nth orbit is given by the formula:
\[ L = n \frac{h}{2\pi} \]
where \( n \) is the principal quantum number (the orbit number) and \( h \) is Planck's constant.

2. **Identify the Orbit Number**: For this question, we are interested in the 5th orbit, which means \( n = 5 \).

3. **Substitute the Value of n**: Plugging in the value of \( n \) into the formula:
\[ L = 5 \frac{h}{2\pi} \]

4. **Simplify the Expression**: This can be simplified to:
\[ L = \frac{5h}{2\pi} \]

5. **Final Result**: Thus, the angular momentum of an electron in the 5th orbit is:
\[ L = \frac{5h}{2\pi} \]