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Arrange the following in decreasing orde...

Arrange the following in decreasing order of their boiling points:
(I) n-Butane
(II) 2-Methylbutane,
(III) n-Pentane
(IV) 2,2-Dimethylpropane

A

IgtIIgtIIIgtIV

B

IIgtIIIgtIVgtI

C

IVgtIIIgtIIgtI

D

IIIgtIIgtIVgtI

Text Solution

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The correct Answer is:
To arrange the compounds n-Butane (I), 2-Methylbutane (II), n-Pentane (III), and 2,2-Dimethylpropane (IV) in decreasing order of their boiling points, we need to consider two main factors: the molar mass of the compounds and the degree of branching in their structures. ### Step 1: Determine the Molar Mass of Each Compound 1. **n-Butane (C4H10)**: - Molar mass = (4 × 12) + (10 × 1) = 58 g/mol 2. **2-Methylbutane (C5H12)**: - Molar mass = (5 × 12) + (12 × 1) = 72 g/mol 3. **n-Pentane (C5H12)**: - Molar mass = (5 × 12) + (12 × 1) = 72 g/mol 4. **2,2-Dimethylpropane (C5H12)**: - Molar mass = (5 × 12) + (12 × 1) = 72 g/mol ### Step 2: Analyze the Degree of Branching - **n-Butane**: No branching, straight-chain structure. - **2-Methylbutane**: One branch, less branched than 2,2-Dimethylpropane. - **n-Pentane**: No branching, straight-chain structure, similar to n-Butane but with more carbons. - **2,2-Dimethylpropane**: Highly branched, which typically leads to lower boiling points. ### Step 3: Compare Boiling Points Based on Molar Mass and Branching - **n-Pentane (III)** has the highest boiling point due to its straight-chain structure and higher molar mass compared to n-Butane. - **2-Methylbutane (II)** has a lower boiling point than n-Pentane but higher than n-Butane due to its branching. - **n-Butane (I)** has a lower boiling point than both 2-Methylbutane and n-Pentane. - **2,2-Dimethylpropane (IV)**, despite having the same molar mass as n-Pentane and 2-Methylbutane, has the lowest boiling point due to its high degree of branching. ### Final Order of Boiling Points 1. n-Pentane (III) - Highest boiling point 2. 2-Methylbutane (II) 3. n-Butane (I) 4. 2,2-Dimethylpropane (IV) - Lowest boiling point ### Conclusion The decreasing order of boiling points is: **n-Pentane (III) > 2-Methylbutane (II) > n-Butane (I) > 2,2-Dimethylpropane (IV)**

To arrange the compounds n-Butane (I), 2-Methylbutane (II), n-Pentane (III), and 2,2-Dimethylpropane (IV) in decreasing order of their boiling points, we need to consider two main factors: the molar mass of the compounds and the degree of branching in their structures. ### Step 1: Determine the Molar Mass of Each Compound 1. **n-Butane (C4H10)**: - Molar mass = (4 × 12) + (10 × 1) = 58 g/mol 2. **2-Methylbutane (C5H12)**: - Molar mass = (5 × 12) + (12 × 1) = 72 g/mol 3. **n-Pentane (C5H12)**: ...
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