An organic compound (X) with molecular formula `C_(3)H_(6)O` is not readily oxidised. On reduction it gives `C_(3)H_(8)O` (Y) which reacts with HBr to give alkyl bromide (Z) which is converted to Grignard reagent. Grignard reagent reacts with (X) to give 2 , 3-dimethylbutan-2-ol. (X), (Y) and (Z) repectively are.

Options

A. `CH_(3)COCH_(3), CH_(3)CH_(2)CH_(2)OH, CH_(3)CH(Br)CH_(3)`
B. `CH_(3)CH_(2)CHO, CH_(3)CH=CH_(2), CH_(3)CH(Br)CH_(3)`
C. `CH_(3)COCH_(3),CH_(3)CH(OH)CH_(3), CH_(3)CH(Br)CH_(3)`
D. `CH_(3)CH_(2)CHO, CH_(3)CH_(2)CH_(2)OH, CH_(3)CH_(2)CH_(2)Br`

Explanation

To solve the problem step by step, we need to identify the compounds (X), (Y), and (Z) based on the information provided.

### Step 1: Identify Compound (X)
The molecular formula of compound (X) is `C3H6O`. The problem states that (X) is not readily oxidized, which suggests that it is a ketone rather than an aldehyde, as aldehydes are easily oxidized. The simplest ketone with the formula `C3H6O` is acetone (CH3COCH3).

**Conclusion:**
(X) = Acetone (CH3COCH3)

### Step 2: Identify Compound (Y)
The problem states that on reduction, (X) gives (Y), which has the formula `C3H8O`. When acetone is reduced, it forms a secondary alcohol. The reduction of acetone leads to the formation of 2-propanol (isopropanol).

**Conclusion:**
(Y) = 2-Propanol (CH3CHOHCH3)

### Step 3: Identify Compound (Z)
Next, we know that (Y) reacts with HBr to form an alkyl bromide (Z). The reaction of 2-propanol with HBr will lead to the formation of 2-bromopropane.

**Conclusion:**
(Z) = 2-Bromopropane (CH3CHBrCH3)

### Step 4: Grignard Reagent Formation
The compound (Z) is then converted to a Grignard reagent. The Grignard reagent formed from 2-bromopropane will be isopropyl magnesium bromide (CH3CH(MgBr)CH3).

### Step 5: Reaction of Grignard Reagent with (X)
The Grignard reagent reacts with (X) (acetone) to give 2,3-dimethylbutan-2-ol. The reaction involves nucleophilic addition of the Grignard reagent to the carbonyl carbon of acetone, followed by hydrolysis.

**Final Conclusion:**
- (X) = Acetone (CH3COCH3)
- (Y) = 2-Propanol (CH3CHOHCH3)
- (Z) = 2-Bromopropane (CH3CHBrCH3)

### Summary
- (X) = Acetone
- (Y) = 2-Propanol
- (Z) = 2-Bromopropane