The final product (Y) in the following sequence of chemical reaction is
`CH_(3)OH overset(Cu)underset(300^(@)C) to X overset(NaOH) to Y +CH_(3)OH`

Options

A. an alkene
B. a carboxylic acid
C. an aldehyde
D. sodium salt of carboxylic acid.

Explanation

To solve the problem, we will break down the sequence of reactions step by step.

### Step 1: Oxidation of Methanol
1. **Starting Material**: Methanol (CH₃OH).
2. **Reagent**: Copper (Cu) at 300°C.
3. **Reaction Type**: Oxidation of a primary alcohol to an aldehyde.
4. **Product**: The oxidation of methanol (a primary alcohol) leads to the formation of formaldehyde (HCHO).

**Hint**: Remember that primary alcohols are oxidized to aldehydes, while secondary alcohols are oxidized to ketones.

### Step 2: Reaction with Sodium Hydroxide
1. **Starting Material**: Formaldehyde (HCHO).
2. **Reagent**: Sodium hydroxide (NaOH).
3. **Reaction Type**: Since formaldehyde has no alpha hydrogen, it undergoes a reaction known as the Cannizzaro reaction.
4. **Product Formation**: In the Cannizzaro reaction, one molecule of formaldehyde is reduced to methanol (CH₃OH), while another molecule is oxidized to formic acid (HCOOH).

**Hint**: The Cannizzaro reaction occurs with aldehydes that lack alpha hydrogens, leading to disproportionation.

### Step 3: Final Product Identification
1. **Products from Step 2**: Methanol (CH₃OH) and formic acid (HCOOH).
2. **Final Product (Y)**: The sodium salt of formic acid is formed when formic acid (HCOOH) reacts with sodium hydroxide (NaOH), resulting in HCOONa.

**Hint**: The sodium salt of a carboxylic acid is formed when the acid reacts with a base.

### Conclusion
The final product (Y) in the sequence of reactions is **sodium formate (HCOONa)**, which is the sodium salt of formic acid.

**Final Answer**: Y = HCOONa (sodium formate).