Complete the reactions with appropriate products.
`CH_(3)CHO+NH_(2)OH to X`
(i)`CH_(3)CHO+NH_(2)OH to X`
(ii) `CH_(2)=CH_(2)+PdCl_(2)+H_(2)O overset(CuCl_(2)) to Y `
(iii) `CH_(3)CH_(2)CH_(2)CH_(2)OH overset(CrO_(3)-H_(2)SO_(4))to Z`

Options

A. `X=CH_(3)CH=NOH, Y=CH_(3)CHO, Z=CH_(3)CH_(2)CH_(2)COOH`
B. `X=CH_(3)CH_(2)NH_(2), Y=CH_(3)CH_(2)CHO, Z=CH_(3)CH_(2)CH_(2)COOH`
C. `X=CH_(3)CONH_(2), Y=HCHO, Z=CH_(3)COCH_(3)`
D. `X=CH_(3)C-=N, Y=CH_(3)CHO, Z=HCOOH`

Answer

Let's break down the reactions step by step to find the products X, Y, and Z.

### Step 1: Reaction of Acetaldehyde with Hydroxylamine
**Reaction:**
\[ \text{CH}_3\text{CHO} + \text{NH}_2\text{OH} \rightarrow X \]

**Explanation:**
Acetaldehyde (CH₃CHO) reacts with hydroxylamine (NH₂OH) to form an oxime. The reaction involves the nucleophilic attack of the nitrogen in hydroxylamine on the carbonyl carbon of acetaldehyde, followed by dehydration to form the double bond.

**Product:**
The product of this reaction is acetyl oxime, which has the structure:
\[ \text{X} = \text{CH}_3\text{C}(=NOH)\text{H} \]
or simply,
\[ \text{X} = \text{CH}_3\text{CH}=\text{NOH} \]

### Step 2: Reaction of Ethene with Palladium Chloride and Water
**Reaction:**
\[ \text{CH}_2=\text{CH}_2 + \text{PdCl}_2 + \text{H}_2\text{O} \overset{\text{CuCl}_2}{\rightarrow} Y \]

**Explanation:**
Ethene (CH₂=CH₂) undergoes a reaction with palladium chloride (PdCl₂) and water in the presence of copper(II) chloride (CuCl₂). This reaction is a hydration reaction that leads to the formation of acetaldehyde through the addition of water across the double bond.

**Product:**
The product of this reaction is acetaldehyde:
\[ \text{Y} = \text{CH}_3\text{CHO} \]

### Step 3: Oxidation of Butanol
**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{OH} \overset{\text{CrO}_3-\text{H}_2\text{SO}_4}{\rightarrow} Z \]

**Explanation:**
Butanol (CH₃CH₂CH₂CH₂OH) is oxidized using chromium trioxide (CrO₃) in sulfuric acid (H₂SO₄), which is known as Jones reagent. This oxidation converts the alcohol into a carboxylic acid.

**Product:**
The product of this reaction is butanoic acid:
\[ \text{Z} = \text{CH}_3\text{CH}_2\text{CH}_2\text{COOH} \]

### Summary of Products
- **X:** Acetyl oxime (CH₃CH=NOH)
- **Y:** Acetaldehyde (CH₃CHO)
- **Z:** Butanoic acid (CH₃CH₂CH₂COOH)

### Final Answer
- **X = CH₃CH=NOH (Acetyl oxime)**
- **Y = CH₃CHO (Acetaldehyde)**
- **Z = CH₃CH₂CH₂COOH (Butanoic acid)**