Calculate the voltage drop across 5 `Omega` resistance and current passing through the zener diode for the circuit given below:

Explanation

Since the voltage across the zener diode `V_(2)=50"volt"`
`therefore` Voltage drop across `5Omega` resistor =120-20=70 volt
`therefore`Current through load resistor of `10kOmega`
`I_(L)=(V_(z))/(R_(L))=(50)/(10kOmega)=5xx10^(-3)amp`
Therefore ,current through the Zener diode
`I_(z)=I-I_(L)=14-5xx10^(-3)` amp=13.996 amp.