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f(x)= {(|x+1|",",x lt -2),(2x+3",",-2 le...

`f(x)= {(|x+1|",",x lt -2),(2x+3",",-2 le x lt 0),(x^(2) + 3",",0 le x lt 3),(x^(3)-15,3 le x):}`. Find at which points, the function f(x) is discontinuous ?

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The correct Answer is:
`x= -2`
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