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y= tan^(-1) ((ax-b)/(bx + a)) " then " ...

`y= tan^(-1) ((ax-b)/(bx + a)) " then " (dy)/(dx)|_(x= -1)`= ………

A

`(1)/(2)`

B

a

C

ab

D

`(b)/(a)`

Text Solution

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The correct Answer is:
A
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