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Find a point on the curve y= (x-3)^(2), ...

Find a point on the curve `y= (x-3)^(2)`, where the tangent is parallel to the chord joining the points (3,0) and (4,1).

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The correct Answer is:
`((7)/(2), (1)/(4))`
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KUMAR PRAKASHAN-CONTINUITY AND DIFFERENTIABILITY-NCERT Exemplar Problems and Solution (Short Answer Type Questions)
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