The acceleration due to gravity on moon is `1//6`th of that on the earth. If the length of the seconds pendulum is 96m on the earth, what is its length on the moon ?

Explanation

For seconds pendulum time period is 2s `T= 2pisqrt((l)/(g))` for simple pendulum time remains constant in both the planets `(l)/(g)` = constant `:. (l_(m))/(g_(m))= (l_(e))/(g_(e))` or `(l_(m))/((g_(e))/(6))= (96)/(g_(e))`
`l_(m)= 16 cm`