In damped oscillatory motion a block of mass 200g is suspended to a spring of force constant `90 N//m` in a medium and damping constant is `40g//s`. Find
time period of oscillation

Explanation

Mass ,= 200g= 0.2 kg force constant k = `90N//m` damping constant `b = 40g//s =0.04 kg//s`.
`sqrt(km)= sqrt(90 xx 0.2)= sqrt(18) kg//s`
Here `b lt lt sqrt(km)`
time period `T= 2pisqrt((m)/(k))= 2pisqrt((0.2)/(90))= 0.3s`