A wire having resistance 20 `Omega` is bent in the form of a circle as shown in the following figure:

What will be the resistance between two end points A and B located on the diameter?

Options

A. `5 Omega`
B. `10 Omega`
C. `20 Omega`
D. ` 40 Omega`

Answer

A

Explanation

The resistance of the wire is R = 20`Omega`.Hence, the resistance of the upper part of the circle `=R/2 = 10 Omega`
Similarly, the resistance of the lower part of the circle `= R/2 = 10 Omega` .

As shown in the figure above, resistors with resistances `10 Omega and 10 Omega` are in parallel. So, the equivalent resistance of the combination will be
`R. = ((10) (10))/(10 + 10) =5 Omega`