Three resistors of resistances `2 Omega, 3 Omega and 5 Omega` are connected in series with 10 V battery. The voltage across `2Omega` resistor will be ………………… .

Options

A. `10 V`
B. `5 V`
C. `3 V`
D. `2 V`

Answer

D

Explanation

The equivalent resistance of the circuit
`R = 2 +3 +5 = 10 Omega`
The current flowing through the circuit
`I = V/R = 10 /10 = 1A`
The voltage across `2 Omega` resistor
`= 2 xx I = 2Omega xx 1A = 2V`