Home
Class 12
MATHS
Show that of all rectangles inscribed in...

Show that of all rectangles inscribed in a given fixed circle, the square has the maximum area.

Answer

Step by step text solution for Show that of all rectangles inscribed in a given fixed circle, the square has the maximum area. by MATHS experts to help you in doubts & scoring excellent marks in Class 12 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    KUMAR PRAKASHAN|Exercise PRACTICE PAPER - 6 (SECTION - D)|2 Videos
  • APPLICATION OF DERIVATIVES

    KUMAR PRAKASHAN|Exercise PRACTICE PAPER - 6 (SECTION - B)|4 Videos
  • ANNUAL EXAMINATION :SAMPLE PAPER

    KUMAR PRAKASHAN|Exercise PART-B ( SECTION-C)|10 Videos
  • APPLICATION OF INTEGRALS

    KUMAR PRAKASHAN|Exercise PRACTICE PAPER ( SECTION -D)|2 Videos

Similar Questions

Explore conceptually related problems

If a triangle ABC, inscribed in a fixed circle, be slightly varied in such away as to have its vertices always on the circle, then show that (d a)/(c a sA)+(d b)/(cosB)+(d c)/(cosC)=0.

Prove that in all rectangles with given area, the perimeter of square is minimum.

What is the area of an equilateral triangle inscribed in a circle of radius 4cm?

In the given figure, ABC is an equilateral triangle inscribed in a circle of radius 4 cm. Find the area of the shaded region.

Show that a triangle of maximum area that can be inscribed in a circle of radius a is an equilateral triangle.

A large number of bullets are fired in all directions with the same speed v . Find the maximum area on the ground on which these bullets will spread.

Find the area of a square inscribed in a circle of radius 8 cm.

Show that the height of the cylinder of maximum volume that can be inscribed in a sphere of radius R is (2R)/(sqrt(3)) . Also find the maximum volume.

Show that semi - vertical angle of right circular cone of given surface area and maximum volume is sin^(-1)((1)/(3)) .

Show that of all line segments drawn from a given point not on a given line, the perpendicular line segment is the shortest.