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Find the equation of a circle whose diameter has the length 20 and the equation of two of its diameters are `2x+y=6 and 3x+2y=4`.

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Q.find the equation of the circle whose diameter has the length 20 and the equation of two of its diameters are 2x+y=6 and 3x+2y=4

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Knowledge Check

  • The equation of the circle passing through the origin is x^(2)+y^(2)-6x+2y=0 . The equation of one of its diameters is

    A
    `x+3y=0`
    B
    `x+y=0`
    C
    `x=y`
    D
    `3x+y=0`

  • The equation of the circle passing through the origin is x^(2)+y^(2)-6x+2y=0 . The equation of one of its diameters is

    A
    `x+3y=0 `
    B
    `x+y=0 `
    C
    `x=y `
    D
    `3x+y=0 `

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    (i) Find the equation of a circle passes through the point (4,3) and whose centre is (-3,2). Find the equation of a circle in which the equations of its two diameters are 2x+y=5 and x-y=1 and its radius is 5 units.

    Find the equations of the circles drawn on the diagonals of the rectangle as its diameter whose sides are x=6,x=-3,y=3 and y=-1

    Find the equation of the circle drawn on the diagonals of the rectangle as its diameter whose sides are : (i) x = 6 , x = - 3, y = 3 and y = - 1 (ii) x = 5 , x = 8 , y = 4 , y = 7 .

    Find the equation of a circle, the equation of whose two diameters are x + y = 6 and 3x +4y =16 and radius is 10.

    Find the equation of the circle whose diameter is the common chord of the circles x^(2) + y^(2) + 2x + 3y + 1 = 0 and x^(2) + y^(2) + 4x + 3y + 2 = 0

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