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The resistance of a platinum resistance ...

The resistance of a platinum resistance thermometer is found to be 11.0 ohm when dipped in a triple point cell. When it is dipped in a bath, the resistance is found to be 28.887 ohm. Find the temperature of the bath in `""^(@)C` on platinum scale.

Text Solution

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In term of triple point of water.
`T_(K) = [ 273.16 (R)/(R_(Tr)) ] K `
so `T_(K) = 273.16 xx (28.887)/(11.0) = 717.32K`
Now as `T_(C) = T_(K) - 273.15`
`T_(C) = 717.32 - 273.15 = 444.17^(0)` C
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