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The energy of an electron in the first B...

The energy of an electron in the first Bohr orbit of H atom is -13.6 eV. The possible energy value(s) of the excited state(s) for electrons in Bohr orbits of hydrogen is (are)

A

`-3.4eV`

B

`-4.2eV`

C

`-6.8eV`

D

`-1.5eV`

Text Solution

Verified by Experts

Energy in an orbit of hydrogen atom, `E_(n)` is given by
`E_(n)=(13.6xxZ^(2))/(n^(2))eV`
For 1st orbit, n = 1 and Z = 1,
Hence `E_(1) = 13.6 eV`. The possible values of energies (in eV) are - 13.6, -3.4, -1.5 ... etc. for n = 1, 2, 3, .. . , etc.
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