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If the length of a simple pendulum is in...

If the length of a simple pendulum is increased by 2%, then the time period

A

increases by 1%

B

decreases by 1%

C

increases by 2%

D

decreases by 2%

Text Solution

Verified by Experts

The correct Answer is:
A
`l_(2) = 1.02 l_(1)`, Time period (T) `=2pi xx sqrt(l/g) prop sqrt(l)`
Therefore `T_(2)/T_(1) = sqrt(I_(2)/I_(1)) = sqrt((1.02 l_(1))/l_(1)) = 1.01`
Thus, time period increased by 1%.
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