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Write equations for the steps in S(N)1 m...

Write equations for the steps in `S_(N)1` mechanism of conversion of tertiary butyl bromide into tertiary butyl alcohol.

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The correct Answer is:
`(##OSW_SP_CHE_XII_C10_E02_009_A01##)`

`S_(N)^(1)` Mechanism: This is a first order Uni-molecular reaction which completes in two steps:
`(H_(3)C)_(3)C-Br +OH_(1) rightarrow (CH_(3))_(3)C-OH+Br ^(-)`
The rate law in Rate `= K [(CH_(3))_(3) C Br]`
Step `1 - (CH_(3))_(3) Leftrightarrow (CH_(3))_(3)C^(+)+Br^(-)` (Slow step)
(tert. butyl bromide)
Step `2 - (CH_(3))_(3) C^(+) + OH^(-)rightarrow (CH_(3))_(3) C-OH`
(tert. butyl alcohol) (fast step)
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