Resistance of 0.05 M electrolytic solution at 298K temperature is 30.0 `Omega`. The cross sectional area of conductivity cell having Pt electrode is `3.8cm^(2)` and distance between two electrode is 1.5 cm, then what is the molar conductivity of electrolytic solution ?

Explanation

Conductivity constant for cell :
`G^(**)=(l)/(A)=(1.5cm)/(3.8cm^(2))=0.3947cm^(-1)`
Where, R=resistance of solution=`30.0Omega`
c=concentration of solution=0.05 mol `L^(-1)`
Conductivity of solution :
`kappa=(G^(**))/(R)=(1.5cm)/(3.8cm^(2))xx(1)/(30Omega)`
`=0.013158cm^(-1)Omega^(-1)~~0.0132" S "cm^(-1)`
Molar conductivity :
`Lamda_(m)=(1000kappa)/(c)=(1000xx0.0132" S "cm^(-1))/(0.05" mol "cm^(-3))`
`=264" S cm"^(2)mol^(-1)`