Reaction : `2Fe^(3+)+Zn to Zn^(2+)+2Fe^(2+)`, is carried out in electrochemical cell, then on increasing concentration of `Fe^(2+)` what will be observed ?

Options

A. Cell potential increases
B. Cell potential decreases
C. Increase in current.
D. pH of solution decreases

Answer

B

Explanation

`E_(cell)=E_(cell)^(o)-(0.0592)/(n)"log"(["The concentration of product"])/(["The concentration of reactant"])`
From above equation, on increasing `Fe^(2+)` concentration, `E_(cell)` value decreases by subtracting from `E_(cell)^(@)` value.