Cell reaction :
`2Fe_((S))+O_(2(g))+4H_((aq))^(+) to 2Fe_((aq))^(2+)+2H_(2)O_((l)),E^(@)=1.67V`
where `[Fe^(2+)]=10^(-3)M,P(O_(2))=0.1 atm` and pH=3, then what is cell potential at `25^(@)C` ?

Options

A. 1.47 V
B. 1.77 V
C. 1.87 V
D. 1.57 V

Answer

D

Explanation

1.57 V