Two electrolytic cell are attached in series and current is passing through them. First electrolytic cell `X(NO_(3))_(3(aq))` and second electrolytic cell posses `Y(NO_(3))_(2)` and molecular mass of X and Y are 1:2 respectively. Hence what is the ratio of lierated mass ?

Options

A. `3:2`
B. `1:2`
C. `1:3`
D. `3:1`

Answer

C

Explanation

Oxidation state of X and Y are `X^(3+) and Y^(2+)` respectively,
Molecular mass ratio=1:2 and so equivalent mass`=(1)/(3):(2)/(2) or 1:3`.