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0.12g organic compound gave 0.22g Mg(2)P...

0.12g organic compound gave 0.22g `Mg_(2)P_(2)O_(7)`. What is the percentage of phosphorus in compound? (P= 31) (Molar mass of `Mg_(2)P_(2)O_(7)= 222g`)

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`2P rarr Mg_(2)P_(2)O_(7)`
% `P =("mass of 2P")/("molar mass of" Mg_(2)P_(2)O_(7)) xx ("mass of "Mg_(2)P_(2)O_(7))/("molar mass of compound") xx 100`
`=(62)/(222) xx (0.22)/(0.12) xx 100= 51.20%`
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