Home
Class 12
MATHS
If area of the triangle with vertices (-...

If area of the triangle with vertices (-2, 0), (0, 4) and (0, k) is 4 square units, find the value of 'k' using determinants.

Text Solution

Verified by Experts

The correct Answer is:
k= 8, 0
Promotional Banner

Topper's Solved these Questions

  • II PUC MATHEMATICS P.U. BOARD LATEST MODEL QUESTION PAPER - 1

    SUNSTAR PUBLICATION|Exercise PART - C|14 Videos

  • II PUC MATHEMATICS P.U. BOARD LATEST MODEL QUESTION PAPER - 1

    SUNSTAR PUBLICATION|Exercise PART - D|9 Videos

  • II PUC MATHEMATICS P.U. BOARD LATEST MODEL QUESTION PAPER - 1

    SUNSTAR PUBLICATION|Exercise PART - E|2 Videos

  • II PUC MATHEMATICS ANNUAL EXAM QUESTION PEPER MARCH -17

    SUNSTAR PUBLICATION|Exercise PART -D|12 Videos

  • II PUC MATHEMATICS SUPPLEMENTARY EXAM QUESTION PAPER JULY - 2017

    SUNSTAR PUBLICATION|Exercise PART-E|2 Videos

Similar Questions

Explore conceptually related problems

If the area of the triangle with vertices (-2, 0), (0, 4) and (0, k) is 4 square units, find the values of k u"sin"g determinants.

If the area of the triangle with vertices (-2, 0) (0, 4) and (0,k) is 4 square units. Find the value of k using determinants.

If the area of the triangle with vertices (2,-6), (5,4) and (k,4) is 35 square units, find values of k using determinants.

If the area of the triangle with vertices (2,-6),(5,4) and (K,4) is 35 sq. units, then find the values of K, using determinants.

If the area of the triangle with vertices (x, 0). (1.1) and (0.2) is 4 square units then a value of

The area of triangle with vertices (K, 0), (4,0), (0, 2) is 4 square units, then value of K is

A triangle with vertices (4, 0), (-1, -1), (3, 5) is :

The area of a triangle with vertices (-3,0),(3,0) and (0,k) is 9 sq. units . The value of k will be :

Find the area of the triangle vertices are (0, 0), (3, 0) and (0, 2)

The area of the triangle with vertices at (-4,1) , (1,2),(4,-3) is