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cos[2"sin"^(-1)3/4+"cos"^(-1)3/4]=...

`cos[2"sin"^(-1)3/4+"cos"^(-1)3/4]=`

A

`3/5`

B

`-3/4`

C

Does not exist

D

`3/4`

Text Solution

Verified by Experts

The correct Answer is:
B
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