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Find the de-Broglie wavelength of an ele...

Find the de-Broglie wavelength of an electron with kinetic energy of 120 eV.

A

124pm

B

112pm

C

102pm

D

95pm

Text Solution

Verified by Experts

The correct Answer is:
B
`lamda= (1.227nm)/(sqrt(120))= (1.227)/(10.95)= 0.1120 xx 10^(-9) = 112pm`
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