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The ratio of angular speed of a second- ...

The ratio of angular speed of a second- hand to the hour-hand of a watch is

A

`72: 1`

B

`3600: 1`

C

`60: 1`

D

`720: 1`

Text Solution

Verified by Experts

The correct Answer is:
D
`omega= (theta)/(t) rArr omega alpha (1)/(t)`
Hence `(omega_(sec))/(omega_("hour"))= (t_("hour"))/(t_(sec))= (12 xx 3600s)/(60s)= 720 therefore omega_(sec): omega_("hour") = 720: 1`
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